(x+5)(x^2+4x-8)

3 min read Jun 17, 2024
(x+5)(x^2+4x-8)

Expanding the Expression (x+5)(x^2+4x-8)

This article will guide you through the process of expanding the given expression: (x+5)(x^2+4x-8).

Understanding the Problem

We have two expressions:

  • (x+5): This is a binomial (an expression with two terms).
  • (x^2+4x-8): This is a trinomial (an expression with three terms).

Our goal is to multiply these two expressions together to obtain a simplified expression.

Using the Distributive Property

The distributive property is the key to expanding the expression. It states that multiplying a sum by a number is the same as multiplying each term of the sum by that number.

Here's how we apply it:

  1. Distribute (x+5) over each term of (x^2+4x-8):

    • x(x^2+4x-8): This represents multiplying the first term of (x+5) with each term of (x^2+4x-8).
    • 5(x^2+4x-8): This represents multiplying the second term of (x+5) with each term of (x^2+4x-8).
  2. Simplify each individual multiplication:

    • x(x^2+4x-8) = x^3 + 4x^2 - 8x
    • 5(x^2+4x-8) = 5x^2 + 20x - 40
  3. Combine the results:

    • (x^3 + 4x^2 - 8x) + (5x^2 + 20x - 40)
  4. Combine like terms:

    • x^3 + (4x^2 + 5x^2) + (-8x + 20x) - 40
  5. Final simplified expression:

    • x^3 + 9x^2 + 12x - 40

Conclusion

By applying the distributive property, we successfully expanded the expression (x+5)(x^2+4x-8) to obtain the simplified form x^3 + 9x^2 + 12x - 40. This process demonstrates the importance of understanding the distributive property in algebra.

Related Post